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fs/mpage: avoid negative shift for large blocksize
For large blocksizes the number of block bits is larger than PAGE_SHIFT, so calculate the sector number from the byte offset instead. This is required to enable large folios with buffer-heads. Reviewed-by: "Matthew Wilcox (Oracle)" <willy@infradead.org> Signed-off-by: Luis Chamberlain <mcgrof@kernel.org> Signed-off-by: Hannes Reinecke <hare@kernel.org> Link: https://lore.kernel.org/r/20250221223823.1680616-4-mcgrof@kernel.org Reviewed-by: Hannes Reinecke <hare@suse.de> Signed-off-by: Christian Brauner <brauner@kernel.org>
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committed by
Christian Brauner
parent
b72e591f74
commit
86c60efd7c
@@ -181,7 +181,7 @@ static struct bio *do_mpage_readpage(struct mpage_readpage_args *args)
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if (folio_buffers(folio))
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goto confused;
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block_in_file = (sector_t)folio->index << (PAGE_SHIFT - blkbits);
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block_in_file = folio_pos(folio) >> blkbits;
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last_block = block_in_file + args->nr_pages * blocks_per_page;
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last_block_in_file = (i_size_read(inode) + blocksize - 1) >> blkbits;
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if (last_block > last_block_in_file)
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@@ -527,7 +527,7 @@ static int __mpage_writepage(struct folio *folio, struct writeback_control *wbc,
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* The page has no buffers: map it to disk
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*/
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BUG_ON(!folio_test_uptodate(folio));
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block_in_file = (sector_t)folio->index << (PAGE_SHIFT - blkbits);
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block_in_file = folio_pos(folio) >> blkbits;
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/*
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* Whole page beyond EOF? Skip allocating blocks to avoid leaking
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* space.
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