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btrfs: remove bogus root search condition in sample_block_group_extent_item()
There's no need to pass the maximum between the block group's start offset and BTRFS_SUPER_INFO_OFFSET (64K) since we can't have any block groups allocated in the first megabyte, as that's reserved space. Furthermore, even if we could, the correct thing to do was to pass the block group's start offset anyway - and that's precisely what we do for block groups that happen to contain superblock mirror (the range for the super block is never marked as free and it's marked as dirty in the fs_info->excluded_extents io tree). So simplify this and get rid of that maximum expression. Reviewed-by: Boris Burkov <boris@bur.io> Reviewed-by: Qu Wenruo <wqu@suse.com> Signed-off-by: Filipe Manana <fdmanana@suse.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
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committed by
David Sterba
parent
7c2830f00c
commit
79d51b5c7a
@@ -606,8 +606,7 @@ static int sample_block_group_extent_item(struct btrfs_caching_control *caching_
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lockdep_assert_held(&caching_ctl->mutex);
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lockdep_assert_held_read(&fs_info->commit_root_sem);
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extent_root = btrfs_extent_root(fs_info, max_t(u64, block_group->start,
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BTRFS_SUPER_INFO_OFFSET));
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extent_root = btrfs_extent_root(fs_info, block_group->start);
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search_offset = index * div_u64(block_group->length, max_index);
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search_key.objectid = block_group->start + search_offset;
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