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btrfs: calculate number of eb pages properly in csum_tree_block
Building with -Warray-bounds on systems with 64K pages there's a
warning:
fs/btrfs/disk-io.c: In function ‘csum_tree_block’:
fs/btrfs/disk-io.c:226:34: warning: array subscript 1 is above array bounds of ‘struct page *[1]’ [-Warray-bounds]
226 | kaddr = page_address(buf->pages[i]);
| ~~~~~~~~~~^~~
./include/linux/mm.h:1630:48: note: in definition of macro ‘page_address’
1630 | #define page_address(page) lowmem_page_address(page)
| ^~~~
In file included from fs/btrfs/ctree.h:32,
from fs/btrfs/disk-io.c:23:
fs/btrfs/extent_io.h:98:15: note: while referencing ‘pages’
98 | struct page *pages[1];
| ^~~~~
The compiler has no way to know that in that case the nodesize is exactly
PAGE_SIZE, so the resulting number of pages will be correct (1).
Let's use num_extent_pages that makes the case nodesize == PAGE_SIZE
explicitly 1.
Reported-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Reviewed-by: Qu Wenruo <wqu@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
@@ -209,7 +209,7 @@ void btrfs_set_buffer_lockdep_class(u64 objectid, struct extent_buffer *eb,
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static void csum_tree_block(struct extent_buffer *buf, u8 *result)
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{
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struct btrfs_fs_info *fs_info = buf->fs_info;
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const int num_pages = fs_info->nodesize >> PAGE_SHIFT;
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const int num_pages = num_extent_pages(buf);
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const int first_page_part = min_t(u32, PAGE_SIZE, fs_info->nodesize);
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SHASH_DESC_ON_STACK(shash, fs_info->csum_shash);
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char *kaddr;
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