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bpf: don't downgrade half-dead scalar zero spills to STACK_ZERO
states.c:__clean_func_state() can downgrade scalar zero spill to
STACK_ZERO in the following case:
*(u64 *)(r10 - 8) = 0;
... checkpoint ...
r1 = *(u32 *)(r10 - 4);
... no reads from r10-8 ...
Here 4 bytes at r10-8 are dead and verifier changes scalar spill to a
combination: 0000pppp (p stands for poison). Such a change breaks
precision propagation chains. All places that produce STACK_ZERO
should call bpf_mark_chain_precision() for the zero source.
This patch fixes the bug in a simplest way possible:
avoids converting stack spills of zero to STACK_ZERO.
Two smarter approaches are possible:
- do bpf_mark_chain_precision() from __clean_func_state()
- check slot liveness information in check_stack_write_fixed_off()
I investigated both and the changes required are a bit tricky,
hence go with a simple fix for the time being.
Fixes: be23266b4a ("bpf: 4-byte precise clean_verifier_state")
Reported-by: Nicholas Carlini <npc@anthropic.com>
Suggested-by: Nicholas Carlini <npc@anthropic.com>
Signed-off-by: Eduard Zingerman <eddyz87@gmail.com>
Link: https://lore.kernel.org/r/20260827-bug-011-cleanfunc-stack-zero-simple-v1-v1-1-c0e996589a52@gmail.com
Signed-off-by: Alexei Starovoitov <ast@kernel.org>
This commit is contained in:
committed by
Alexei Starovoitov
parent
ce6dcd0aed
commit
2f3536bff8
@@ -445,22 +445,19 @@ static void __clean_func_state(struct bpf_verifier_env *env,
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struct bpf_reg_state *spill = &st->stack[i].spilled_ptr;
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if (lo_live && stype == STACK_SPILL) {
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u8 val = STACK_MISC;
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if (spill->type != SCALAR_VALUE)
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continue;
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/*
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* 8 byte spill of scalar 0 where half slot is dead
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* should become STACK_ZERO in lo 4 bytes.
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* Can't replace with STACK_ZERO, because
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* that requires bpf_mark_chain_precision().
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*/
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if (bpf_register_is_null(spill))
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val = STACK_ZERO;
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continue;
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for (j = 0; j < 4; j++) {
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u8 *t = &st->stack[i].slot_type[j];
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if (*t == STACK_SPILL)
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*t = val;
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*t = STACK_MISC;
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}
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}
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bpf_mark_reg_not_init(env, spill);
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