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53 lines
2.4 KiB
TypeScript
53 lines
2.4 KiB
TypeScript
// Copyright (c) 2026, Compiler Explorer Authors
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// All rights reserved.
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//
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// Redistribution and use in source and binary forms, with or without
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// modification, are permitted provided that the following conditions are met:
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//
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// * Redistributions of source code must retain the above copyright notice,
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// this list of conditions and the following disclaimer.
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// * Redistributions in binary form must reproduce the above copyright
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// notice, this list of conditions and the following disclaimer in the
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// documentation and/or other materials provided with the distribution.
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//
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// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
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// AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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// IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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// ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT HOLDER OR CONTRIBUTORS BE
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// LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
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// CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF
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// SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS
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// INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN
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// CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE)
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// ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE
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// POSSIBILITY OF SUCH DAMAGE.
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/**
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* Extract the short link id from a `/z/<id>` URL or path.
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*
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* Accepts a full URL (`https://godbolt.org/z/abc`), a path (`/z/abc`), or a
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* bare id (`abc`), and correctly ignores query strings, fragments and trailing
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* slashes — the pitfalls of the various ad-hoc `lastIndexOf('/z/')` / regex
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* implementations this replaces.
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*/
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export function extractShortId(input: string): string {
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let pathname = input;
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try {
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// Works for absolute URLs; throws for paths/bare ids.
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pathname = new URL(input).pathname;
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} catch {
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// Not an absolute URL — treat the input as a path and drop any
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// query string or fragment ourselves.
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pathname = input.split(/[?#]/)[0];
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}
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const segments = pathname.split('/').filter(Boolean);
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const zIdx = segments.lastIndexOf('z');
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if (zIdx >= 0 && zIdx < segments.length - 1) {
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return segments[zIdx + 1];
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}
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// No `/z/<id>` structure: fall back to the last path segment, or the
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// original input if there were no segments at all.
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return segments.at(-1) ?? input;
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}
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